The sum of the angle measures of the polygon is 540°. Write and solve an equation to find the value of 2. 5x – 8°

4x°

96°

44°

5x + 2°

x = 29°

The angles are  137° , 116° , 96° , 44° and 147°

Step-by-step explanation:

The sum of the angles of the polygon is given as 540°. The angles are given as 5x – 8°,  4x° , 96° , 44°, 5x + 2. Therefore, the value of x can be found as follows

5x – 8° + 4x°  + 96° + 44° + 5x + 2° = 540°

collect like terms

5x + 4x + 5x - 8 + 96 + 44 + 2 = 540°

14x + 134 = 540°

14x = 540 - 134

14x = 406

divide both sides by 14

x = 406/14

x = 29°

Therefore, the angles are as follows

29 × 5 - 8 = 137°

29 × 4 = 116°

96°

44°

5 × 29 + 2 = 147°

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2