Margo spends 0.25 of her paycheck on a new dress, One-eighth of her paycheck on shoes, and $24 on a birthday present. If she spent $60 altogether, how much was Margo’s paycheck? $96 or $160 or $216 or $504?

$96

Step-by-step explanation:

Use the answer choices and test each one

If you test $96 for the paycheck, it works

96/4 = 24

96/8 = 12

24 + 12 = 36

36 + 24 = 60

This option is right because she spent $60 total

margo's pay was $96 dollars

Step-by-step explanation:

Let 'x' represent the amount of Margo's paycheck.  Since she spent 0.25 on a dress, 1/8 (0.125) on shoes and another $24 on a present for a total of $60, we can set up the following equation:

0.25x + 0.125x + 24 = 60

Combine like terms:  0.375x + 24 = 60

Subtract 24 from both sides: 0.375x + 24 - 24 = 60-24 or 0.375x = 36

Divide by 0.375: 0.375x/0.375 = 36/0.375

Solve for x: x = $96

please mark me brainliest :)

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}