Find the length of the portion of the line y = 4 that lies inside a circle of radius 7 centered at the origin

2sqrt(33)

Step-by-step explanation:

We want to find the length of the line y = 4 in the circle x^2+y^2=49.

Substitute y = 4 to get x^2 = 33, so x = sqrt(33) or -sqrt(33).

That means the total length is sqrt(33) * 2 = 2sqrt(33).

Hope that helped,

-sirswagger21

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.