In the diagram, the circle will be dilated by a scale factor of 3 about the origin. The points C, A, and B map to C, A', and B'after the dilation. What is the length of C'B? Use the distance formula to help you decide: d = 16x2 - xx) +(y2 - Yo)?

A = (8.15)

B = (12, 13)

C = (8.10)

A.
5 units
B.
15 units
C. 21 units
D. 24 units
E. 45 units

length of C'B' = 15units (B)

Step-by-step explanation:

Original image is ∆ABC

A = (8,15)

B = (12, 13)

C = (8,10)

Scale factor = 3

Since the circle would be dilated by a scale factor of 3 about the origin, Do(x,y) →3(x,y)

Coordinates of ∆A'B'C'

A' = 3(8, 15) = (24, 45)

B' = 3(12, 13) = (36, 39)

C' = 3(8, 10) = (24, 30)

The distance formula = √(x2 - x1)² + (y2-y1)²

Where x2 = x subscript 2, x1 = x subscript 1; y2 = y subscript 2, y1 = y subscript 1

Length C'B' = Distance between B' and C'

See attachment for details

From the solution, length of C'B' = 15units (B)

-1/2 +2

step-by-step explanation: