The final exam grade of a mathematics class has a normal distribution with mean of 81 and standard deviation of 6.6. If a random sample of 40 students selected from this class, then what is the probability that the average final exam grade of this sample is between 77 and 82? (round to 4 decimal places)

The probability that the average final exam grade of this sample is between 77 and 82

P(77≤ x⁻≤ 82 =  0.8315 or 83%

Step-by-step explanation:

Step(i):-

Given random sample size 'n' = 40

Mean of the normal distribution = 81

Standard deviation of normal distribution = 6.6

Let x₁⁻ = 77

Z₁ = -3.83

Let x₂⁻ = 77

Z₂ = 0.958

The probability that the average final exam grade of this sample is between 77 and 82

P(77≤ x≤ 82) = P( -3.83 ≤x≤0.958)

                    = A( 0.958) + A(3.83)

                   = 0.3315 + 0.4995

                   = 0.8315

The probability that the average final exam grade of this sample is between 77 and 82  = 0.8315 or 83%

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!

need more detail

step-by-step explanation:

lele