The points (-1,4) and (2,-3) are adjacent vertices of a square. What is the area of the square? PLEASE HELP ILL GIVE BRAINLIEST

137 units^2.

Step-by-step explanation:

A and B are positioned according to their coordinates, in the X and Y axes Imagine a right angled triangle, where the actual distance between the two points is the hypotenuse, and the other two sides are the distances in the “X” and “Y” axes that separate the two points.

In the “X” axis, they’re separated by 3 -(-1) units that’s 4…

In the “Y” axis, they’re separated by 4 - (-7) units that’s 11…

Now we have the lengths of two sides of the triangle, we can calculate the length of the hypotenuse… But why would we? we’ve been asked for the area of the square, and adding the areas of the squares on the other two sides gives our answer-

4^2 + 11^ 2 = 16 + 121, = 137 units^2. You didn’t specify units, so we don’t know what the area is, we just have a numerical value.

58

Step-by-step explanation:

The distance between (-1,4) and (2,-3) is sqrt 58. Square that to be 58