Wyatt’s eye-level height is 120 ft above sea level, and Shawn’s eye-level height is 270 ft above sea level. How much farther can Shawn see to the horizon? Use the formula d = StartRoot StartFraction 3 h Over 2 EndFraction EndRoot, h greater-than-or-equal-to 0 with d being the distance they can see in miles and h being their eye-level height in feet.

3√5 miles

Step-by-step explanation:

We are given the formula as;

d = √(3h/2)

Wyatt:

His eye level is 120 ft above sea level, so;

h = 120 ft

Hence;

d = √(3 × 120/2)

d = √180

d = √(36 × 5)

d = √36 × √5

d = 6√5 miles

Shawn:

His eye level is 270 ft above sea level, so;

h = 270 ft

d = √(3 × 270/2)

d = √405

d = √(81 × 5)

d = √81 × √5

d = 9√5 miles

So to find how much farther Shawn can see to the horizon, we'll subtract the value of d of wyatt from that of shawn.

Thus;

Shawn - Wyatt = 9√5 - 6√5 = 3√5 miles

step-by-step explanation:

your question is incomplete, write all the numbers in the sequence that it tells you.  

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