Find the range of values for which
x2–5x + 6 < 0

here, we are required to find the range of values for which

The range of values for which x²–5x + 6 < 0

is at;x < 3

x2–5x + 6 < 0

By solving the expression quadratically; we have;

x² -3x -2x +6 < 0

By factorization;

(x - 2)(x - 3) < 0

Therefore;

The range of values for which x²–5x + 6 < 0

is at;

x < 3

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-2<x<3

or x∈(-2,3)

Step-by-step explanation:

x²-5x<-6

add (-5/2)² i.e.,25/4

x²-5x+25/4<-6+25/4

(x-5/2)²<(-24+25)/4

(x-5/2)²<1/4

(x-5/2)²<(1/2)²

|x-5/2|<1/2

-1/2<x-5/2<1/2

Add 5/2

-1/2+5/2<x-5/2+5/2<1/2+5/2

-2<x<3

i would pic false cause it goes down towards negative

step-by-step explanation:

b. x + 1

step-by-step explanation:

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