Four different positive integers have a product of 110.
What is the sum of the four integers?

Given:

Four different positive intergers as a product of 110

To find:

The sumnof the four numbers whose product is 110

Solution:

1) To find the number we have to find the prime factorization of the given number 110

2) Prime factorization of 110 is

110 = 1×2 × 5 = 11

3) So the four numbers whose product is 110 are 1,2,5 and 11

4) The sum of number's are

1+2+5+11=19

the dimensions are:

step-by-step explanation:

we want to find the dimensions of a rectangular box with volume of

we factor to obtain;

we rewrite the rightmost factor to obtain;

recall that:

we apply difference of two squares formula to obtain;

hence the dimensions are

answer: a

step-by-step explanation: