The students in Marly’s math class recorded the dimensions of their bedrooms in a frequency table. 2-column table with 5 rows. First column labeled area (square feet) with entries 60 is less than or equal to A is less than 80, 80 is less than or equal to A is less than 100, 100 is less than or equal to A is less than 120, 120 is less than or equal to A is less than 140, 140 is less than or equal to A is less than 160. Second column labeled number of rooms with entries 4,6,5,3,1. Create a histogram to represent the data. Which statement is most likely true about the mean and the median of the data?

The histogram is right-skewed, so the mean is greater than the median.

Step-by-step explanation:

Solution

Plotting the histogram, it is evident that the distribution is right skewed or positive skewed.

The distribution is not symmetric around the mean, the tail of the distribution on the right hand (positive) side is longer than on the left hand side. For a right skewed distribution, the mean is typically greater than the median.

So, it this case the histogram is right-skewed, so the mean is greater than the median.

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amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation:

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