Wayne's service center operates a welding shop. Assume that the arrival of jobs follows a Poisson distribution with 2 jobs arriving in an 8 hour day. The time required to complete a job follows a normal distribution with a mean time of 3.2 hours and a standard deviation of 2 hours. A. What is the mean service rate in jobs per hour?
B. What is the average number of jobs waiting for service?
C. What is the average time a job waits before the welder can begin working on it?
D. What is the average number of hours between when a job is received and when it is completed?
E. What percentage of the time is Gubser's welder busy?

a) 0.3125 per hour

b) 2.225 hours

c) 8.9 hours

d) 12.1 hours

e) 80%

Step-by-step explanation:

Given that:

mean time = 3.2 hours, standard deviation (σ) = 2 hours

The  mean service rate in jobs per hour (λ) = 2 jobs/ 8 hour = 0.25 job/hour

a) The average number of jobs waiting for service (μ)= 1/ mean time = 1/ 3.2 = 0.3125 per hour

b) The average time a job waits before the welder can begin working on it (L) is given by:

c) The average number of hours between when a job is received and when it is completed (Wq) is given as:

d) The average number of hours between when a job is received and when it is completed (W) is given as:

e) Percentage of the time is Gubser's welder busy (P) is given as:

answer: 193

explanation:

200-7 = 193

answer. d.289 hope that