What is the standard form for the quadratic function? f(x)=(x−3)2+5 f(x)=x2−4 f(x)=x2+14
f(x)=x2−6x+14
f(x)=x2+6x−4

x^2-6x + 14

Step-by-step explanation:

Here, we want to

write the standard form of the quadratic equation in the question.

This can be written by expanding the bracket.

F(x) = (x-3)^2 +5

F(x) = (x-3)(x-3) + 5

F(x) = x(x-3)-3(x-3) +5

F(x) = x^2 -3x-3x + 9 + 5 = x^2-6x + 14

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

twenty-six miles over two gallons because the proportion for the original 13 miles to one gallon would be written 13/1 and, doing the same thing to the top and bottom, i multiplied by 2 and got 26/2