Help please? I can’t figure this out

Step-by-step explanation:

surface area=2×area of trapezoid(front and back)+area of base (rectangle)+area of top (area of two rectangles)+area of side rectangle

surface area=2[(8+6+8)/2×7]+(8+6)×6+(8+9)×6+7×6

=2×77+14×6+17×6+7×6

=154+84+102+42

=382 cm²

front is made of rectangle and a triangle.

together they make a trapezoid with parallel sides 14 (8+6) and 8

area of trapezoid=(sum of parallel sides)/2×length of perpendicular between parallel sides (here 7)

=(14+8)/2×7=77

area of two trapezoids (front and back)=2×77=154 cm²

base contains two rectangles (8×6 and 6×6)

area of base=8×6+6×6=48+36=84  cm²

Top contains two rectangles (8×6 and 9×6)

area of top=8×6+9×6=48+54=102 cm²

area of side rectangle=7×6=42 cm²

Total surface area=154+84+102+42=382 cm²

the answer will be b x² +x-1

step-by-step explanation: