Find the perimeter of this figure to the nearest hundredth use 3.14 to approximate pi P=?ft

48.57 ft

Step-by-step explanation:

Perimeter of Rectangle:

=> 2L+2B

Where L is length and B is Breadth

=> 2(10)+2(8)

=> 20+16

=> 36 ft

Here, Perimeter of Semi-circle:

=> πD/2

Where D = 8

=> (3.14)(8)/2

=> 12.57 ft

Perimeter of the figure

=> 36+12.57 = 48.57 ft

the answer will be

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.