Please help me with this math problem

y = x+2

Step-by-step explanation:

First find the slope using two points (0,2) and (5,7)

m = (y2-y1)/(x2-x1)

    = (7-2)/(5-0)

    = 5/5

   = 1

We have the y intercept ( where it crosses the y axis) =2

y = mx+b where m is the slope and b is the y intercept

y = 1x +2

y = x+2

Explanation:

The two red points are (0,2) and (5,7)

Find the slope of the line through (x1,y1) = (0,2) and (x2,y2) = (5,7)

Use the slope formula

m = (y2 - y1)/(x2 - x1)

m = (7 - 2)/(5 - 0)

m = 5/5

m = 1

The slope is m = 1.

The y intercept is b = 2 as this is where the diagonal line cuts through the y axis.

Therefore y = mx+b turns into y = 1x+2, which is the same as y = x+2

This says: "whatever the input x is, add 2 to it to get the y output". So for instance, if the input is x = 5, then we add on 2 to get y = x+2 = 5+2 = 7. This shows how (5,7) is one point on the diagonal line.

answer: 0,6

step-by-step explanation:

this would make it the y intercept.

step-by-step explanation:

to find if any function is an inverse of the other, put the first equation in as x in the next one. then simplify and solve. if at the end you get the statement y = x, then it is an inverse. if you get anything else, it is not.