the graph of F(x), shown below, has the same shape as the graph of G(x)=x^2. but it is shifted up 4 units and to the right 2 units. What is its equation

Step-by-step explanation:

The graph of in vertex form is where h and k, the vertex, is (0, 0). If we shift the parabola right or left, or up or down, the h and k values take on that reflection. If we move up 4, k goes from a value of 0 to a value of 4; if we move right 2 units, h goes from a value of 0 to a value of 2. Putting that together in work (aka vertex) form:

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15