One length of a rectangular garden lies along a patio wall. However, the rest of the garden is enclosed by 28 feet of fencing. If the length of the garden is twice its width, what is the area of the garden?

The area of rectangle is 98 ft.sq.

Step-by-step explanation:

We are given one length of a rectangular garden lies along a patio wall.

Let the width of garden be x

Length of garden = Twice its width=2x

Length garden enclosed by fencing =l+2b=2x+2x= 4x

We are given that the rest of the garden is enclosed by 28 feet of fencing.

So,4x=28

x=7

Width of garden = 7 feet

length of garden = 2x=2(7)=14 feet

Area of garden =

Hence The area of rectangle is 98 ft.sq.

b

step-by-step explanation:

given

- 2 (3x + 12y - 5 - 17x - 16y + 4 )

simplify the parenthesis by collecting like terms

= - 2 (- 14x - 4y - 1) ← distribute the parenthesis by - 2

= 28x + 8y + 2 → b

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .