Milk and cream are mixed together for a recipe. The total volume of the mixture is 1 cup. If the milk contains 2% fat, the cream contains 18% fat, and the mixture contains 6% fat, how much cream is in the mixture? StartFraction 1 Over 5 EndFraction cup. cup StartFraction 1 Over 4 EndFraction cup. cup StartFraction 3 Over 4 EndFraction cup. cup StartFraction 4 Over 5 EndFraction cup. cup

1/4

Step-by-step explanation:

Let the volume of mixture (6%fat) in cup is 100cc

x cc be the volume of cream (18% fat) in the mixture.

∴

(100−x) cc be the volume of milk (2% fat) in the mixture.

x * 0.18+(100−x) * 0.02=100

⋅0.06 or 0.18x − 0.02x = 6−2 or 0.16x

= 4 or x=25 cc = 25%

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1