triangle PQR with side p across from angle P, side q across from angle Q, and side r across from angle R If ∠P measures 27°, ∠R measures 135°, and p equals 9.5, then which length can be found using the Law of Sines? p r RQ PR

side r

Step-by-step explanation:

Using the Law of Sines in Δ PQR, that is

= =

Given ∠ P, ∠ R and p then side r can be found

= , substitute values

= ( cross- multiply )

r sin27° = 9.5 sin135° ( divide both sides by sin27° )

r = ≈ 14.8 ( to 1 dec. place

a: 1/6, j: 1/4

step-by-step explanation: you are welcome

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4