The figure shows the dimensions of a wall having a door and window of a room. Write an algebraic expression for the area of the wall to be painted. PLEASE FAST

Area of the wall to be painted = (11x² + 12x) square units

Step-by-step explanation:

The figure that should be attached to this question is missing. The figure was obtained and is attached to this solution provided.

From the image attached, it is given that the dimension of the rectangular wall to be painted is (4x+3) by (4x), the dimensions of the window is (2x) by (x) and the dimensions of the door is (x) by (3x).

Since, the window space and the door space cannot be painted along with the wall, the Area of the rectangular wall that will be painted will be given by the expression

(Total Area of the rectangular wall) - [(Area of window space) + (Area of door space)]

Area of a rectangular figure = Length × Breadth

Total area of rectangular wall = (4x+3) × 4x = (16x² + 12x) square units

Area of window space = (2x) × (x) = (2x²) square units

Area of door space = (x) × (3x) = (3x²) square units

Area of the wall to be painted = (16x² + 12x) - (2x² + 3x²)

= 16x² + 12x - 5x²

= (11x² + 12x) square units

Hope this Helps!!!

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step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)