A firm employing 100 workers has an average absenteeism of 4%. on a given day what is the probability of no workers being absent

1.69% to the nearest hundredth.

Step-by-step explanation:

Binomial probability distribution.

P(r) = nCr p^r(1-p)^(n-r)    where r = number of successes , n = number of trials and p =probability of success.

So here we have:

Probability of no workers being absent =

P(0) = 100C0*0.04^0 * (0.96)^100

=  1*1*0.0169

= 1.69 %.

the answer is two. hope this !