Point C ∈ AB and AB = 35 cm. The distance from C to A is 6 cm longer than the distance from C to B. Find AC and CB.

AC = 20.5

BC = 14.5

Step-by-step explanation:

The distance from C to A is 6 cm longer than the distance from C to B.  gives us the following equation

AC = BC +6

We know the distance of the two segments gives us the total segment

AB = AC + BC

The total segment is AB =35

Substituting into AB= 35 and AC = BC+6

AB = AC + BC  

35 = (BC+6) + BC

Combing like terms

35 = 2 BC +6

Subtract 6 from each side

29 = 2 BC

Divide by 2

14.5 = BC

Now find AC

AC = BC+6

AC = 14.5+6 = 20.5

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Step-by-step explanation:

AC=20.5

CB=14.5

:)

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x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17