Which congruence theorem would complete the proof shown? SSS SAS ASA

Answer : ASA congruence theorem would complete the proof shown.

Step-by-step explanation :

The following combinations of the congruent triangle facts  will be sufficient to prove triangles congruent.

The combinations are:

(1) SSS (side-side-side) : If three sides of a triangle are congruent to three sides of another triangle then the triangles are congruent.

(2) SAS (side-angle-side) : If two sides and included angle of a triangle are congruent to another triangle then the triangles are congruent.

(3) ASA (angle-side-angle) : If two angles and included side of a triangle are congruent to another triangle then the triangles are congruent.

(4) RHS (right angle-hypotenuse-side) : If the hypotenuse and leg of one right triangle are congruent to the corresponding parts of another right triangle, the right triangles are congruent.

As we are given two triangles.

Prove : ΔDAC ≅ ΔBAC

As,

Side CA = Side CA    (side)

∠2 = ∠3                     (angle)

∠1 = ∠4                      (angle)

That means, in this two angles and included side of a triangle are equal to another triangle then the triangles are congruent.

So, ΔDAC ≅ ΔBAC    (by ASA rule)

Hence, ASA congruence theorem would complete the proof shown.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

answer: no, but if it does it's a obvious pattern.

step-by-step explanation: