A helicopter departs from an airport flying at a speed of 90 miles per hour at a bearing of 250 degrees for 20 minutes before landing on a helipad. Determine the helipad's location in relation to the airport. Round to the mearest tenth of a mile. Show work and reasoning.

30 miles, S70°W of the airport

Step-by-step explanation:

speed of helicopter = 90 miles/hr

1 hr = 60 min, therefore

speed of helicopter = 90/60 = 1.5 miles/min

time  spent in flight = 20 min

bearing of flight path = 250°

since 20 min is spent in flight at a speed of 1.5 miles/min,

distance traveled by the helicopter = speed x time = 1.5 x 20

distance traveled by the helicopter = 30 miles

The bearing of 250° is equivalent to 270 - 250 = 20° (due to the bearing of the third quadrant that is 270°) in the third quadrant of the circle formed around the airport.

This means that it makes an angle of 90 - 20 = 70° (due to the angle within a quadrant which is 90°) with the south pointing cardinal.

The location of the helipad, from the airport can be summed up as 30 miles, south 70° west of the airport. It is written technically as

30 miles, S70°W of the airport

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

it has changed from the width and the height.

step-by-step explanation: