Mathematics, 27.06.2020 21:01 ogc2001
Below is a seven-step proof of part (b) of Theorem 4.1.1. Justify each step either by stating that it is true by hypothesis or by specifying which of the ten vector space axioms applies. Hypothesis: Let u be any vector in a vector space V, let 0 be the zero vector in V, and let k be a scalar.
Conclusion: Then K0= 0
Proof:
(1) K0+Ku = K(0+u)
(2) = Ku
(3) Since ku is in V. -ku is in V
(4) Therefore, (ko+ku)+(-ku) = ku+(-ku)
(5) (ko+ku)+(-ku) = ku+(-ku)
(6) ko+0= 0
(7) k0 = 0
Answers: 1
Mathematics, 21.06.2019 20:00
Ialready asked this but i never got an answer. will give a high rating and perhaps brainliest. choose the linear inequality that describes the graph. the gray area represents the shaded region. y ≤ –4x – 2 y > –4x – 2 y ≥ –4x – 2 y < 4x – 2
Answers: 1
Mathematics, 21.06.2019 20:10
21 type the correct answer in the box. use numerals instead of words. if necessary, use / for the fraction bar. the solution set of n2 - 14n = -45 is { (separate the solutions with a comma)
Answers: 3
Below is a seven-step proof of part (b) of Theorem 4.1.1. Justify each step either by stating that i...
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