In a coffee shop "Scratch and Win" contest, one out of three cards is a winner. What is the probability that Shenice would first win on her third try? a.4/9

b. 1/27

c.4/27

d. 8/81

C.) 4/27

Step-by-step explanation:

Given that:

One out of three cards is a winner :

P(winning) = 1 / 3

Therefore, P(not winning) = P(losing) :

1 - P(winning) = 1 - 1/3 = 2/3

Probability that shenice will first win on her third try can be interpreted as:

1st try = lose, 2nd try: lose, 3rd try : win

P(losing) × p(losing) × p(winning)

(2/3) × (2/3) × (1/3)

4 / 27

Probability of first winning on third try = 4/27

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^