What is the general form of the equation of the line shown? 2 x - y + 3 = 0 2 x - y - 3 = 0 x - 2 y - 3 = 0

2x - y - 3 = 0

Step-by-step explanation:

Find slope-intercept form first: y = mx + b

Step 1: Pick out 2 points

In this case, I picked out (2, 1) and (0, -3) from the graph

Step 2: Using slope formula y2 - y1/x2 - x1 to find slope

-3 - 1/0 - 2

m = 2

Step 3: Place slope formula results into point-slope form

y = 2x + b

Step 4: Plug in a point to find b

-3 = 2(0) + b

b = -3

Step 5: Write slope-intercept form

y = 2x - 3

Step 6: Move all variables and constants to one side

0 = 2x - 3 - y

Step 7: Rearrange

2x - y - 3 = 0 is your answer

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)