Problem 7.1 (10 points) Let pXnqn"0,1,... be a Markov chain with state space S " t1, 2, 3u and transition probability matrix P " ¨ ˝ 0.5 0.4 0.1 0.3 0.4 0.3 0.2 0.3 0.5 ˛ ‚. (a) Compute the stationary distribution π. (b) Is the stationary distribution π also the limiting distribution? Give a reason for your answer.

i think it would be 43 movies that would have to be watched.

step-by-step explanation:

think about it. for the second plan, every month is 8 dollars. 8 x 12= 96. so thats the number for the second plan. now for the first plan, its annual meaning you have to pay 10 dollars every year. so now you have to get an equivalent amount of 86 since 96-10=86. 86 divided by 2 since every movie costs 2$ then you would have to watch 43 movies a year to get the same as the second plan. i really hoped this . have a wonderful day as well!

b

step-by-step explanation:

the answer is 40.

proof: