What value of n makes the equation true? (2x^9Y^n)(4x^2y^10) – 8x^11y^20
O 1
O 2
O 10
O 30

(Brainle pl)

10

explaniion:

given that:

(2x^9y^n)(4x^2y^10)=8x^11y^20

the value of n that will make the inequality true will be found as follows;

(2x^9y^n)(4x^2y^10)=8x^11y^(n+10)

thus;

8x^11y^(n+10)=8x^11y^20

dividing through by 8x^11 we get;

y^(n+10)=y^20

introducing the natural logs we get;

(n+10)lny=20lny

lny will cancel out and we shall remain with;

n+10=20

thus

n=20-10

n=10

the answer is n=10

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19