An angle measures 60° more than the measure of its complementary angle. What is the measure of each angle?

150°

Step-by-step explanation:

a complementary angle is 90°

so 60°+ 90°

is 150°

i hope this helps

The correct answer is 15° and 75°.

Step-by-step explanation:

n  +  n  + 60°  = 90°

2n  + 60°  = 90°

2n  + 60°  − 60°  =  90° − 60°

2 n  = 30°

2n  ÷ 2  =  30° ÷ 2

n  = 15°

The first angle measures 15°. Now plug in n = 15° to find the measure of the other angle, n + 60°.

n  + 60°  =  15° + 60°  = 75°

So, the two angles measure 15° and 75°.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.