In this experiment, you will be using two coins as a simulation for a real-world compound event. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats. What is the theoretical probability that the family has two dogs or two cats? Describe how to use two coins to simulate which two pets the family has. Flip both coins 50 times and record your data in a table like the one below. Result Frequency Heads, Heads Heads, Tails Tails, Heads Tails, Tails Total 50 4.Based on your data, what is the experimental probability that the family has two dogs or two cats? 5.If the family has three pets, what is the theoretical probability that they have three dogs or three cats? 6.How could you change the simulation to generate data for three pets?

lol we need to see what the question is asking about

step-by-step explanation:

dude thats to long figure it

step-by-step explanation:

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages