g A supermarket has three employees who equally packages and weighs produce. Employee A records the correct weight 96% of the time. Employees B and C record the correct weight 95% and 94% of the time, respectively. One customer complains about the incorrect weight recorded on a package he has purchased. What is the probability that the package was weighed by Employee C?

40% probability that the package was weighed by Employee C

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Incorrect package.

Event B: Weighed by Employee C.

A supermarket has three employees who equally packages and weighs produce.

This means that

Employee C records the correct weight 94% of the time

So incorrectly 6% of the time, which means that

Probability of an incorrect package:

4% of 1/3(A)

5% of 1/3(B)

6% of 1/3(C)

So

What is the probability that the package was weighed by Employee C?

40% probability that the package was weighed by Employee C

its totaly b

your welcome btw

answer:   x*94 +688*6   = 267*100

94x+4128=26700    

94x=22572     /94

x=240.128

step-by-step explanation: mark as brainlest reallly need it thx