Solve these equations below simultaneously:y=x^2;y=x+2

(x, y) = (2, 4) or (-1, 1)

Step-by-step explanation:

y = x^2

y = x + 2

=> x^2 = x + 2

Transfer all terms to the left, we have:

=> x^2 - x - 2 = 0

Perform some modifications, we have:

=> x^2 + x - 2x - 2 = 0

Let's group the left-side terms up.

=> x(x + 1) - 2(x + 1) = 0

=> (x - 2)(x + 1) = 0

=> x = 2 => y = x + 2 = 2 + 2 = 4

=> x = -1 => y = x + 2 = -1 + 2 = 1

=> Solution is (x, y) = (2, 4) or (-1, 1)

Hope this helps!

26?

step-by-step explanation:

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.