This is a simultaneous equation question. answer and steps plz.

Number of 10 cent coins = 14

Number of 50 cent coins = 7

Step-by-step explanation:

Let the number of coins of 10 cents = a

and the number of coins of 50 cents = b

Total count of coins = 21

a + b = 21  (1)

Value of 10 cent coins = $0.10

Value of a coins of 10 cents = 0.10a

Value of 50 cent coins = $0.50

Value of b coins of 50 cents = 0.50a

The value of these coins = $4.90

0.10a + 0.50b = 4.90

a + 5b = 49 (2)

By subtracting equation (1) from equation (2)

(a + 5b) - (a + b) = 49 - 21

4b = 28

b = 7

From equation (1),

a + 7 = 21

a = 21 - 7

a = 14

Therefore, number of 10 cents coins = 14

number of 50 cent coins = 7

the answer is ! ?

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: