Which expression is equal to -3b^4(6b^-8)? Assume b=/0

-18 b^-4= -18/b^4

Step-by-step explanation:

-3b^4(6b^-8)

Combine coefficients

-3*6 = -18

Combine exponents since the bases are the same, x^y * x^z = x^(x+z)

b^4 *b^ -8

b^(4+-8)

b^ -4

Put back together

-18 b^-4

We also know that x^-y = 1/x^y

-18/b^4

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

answer: y = 3/2 x - 3

y = 1/8 x - 3/4 that would be your correct option

step-by-step explanation: w