A set of data includes 98 data points ranging from 0 – 160. If the data is split into classes with a range of 10 (1 – 10, 11 – 20, etc), and there are no values that fall in the class 81 – 90, what can you say about the data? A. median could be in the range 81 – 90. B. All the data lies below 80. C. The mean of the data will not be between 81 – 90. D. The relative frequency of the class 81 – 90 is 0.

ik how do do this just give me a few minutes and i will give it to

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

i suppose it should be (y=2x-5)

step-by-step explanation: