What is the range of the function y=
= VX+5?
Oy2-5
Oy20
O yzv5
Oy25

A)  y² -5

The range of the given function x = y² -5

Step-by-step explanation:

Explanation:-

Given f(x) = √x +5

Let y = f(x) = √x +5

    y = √x +5

   squaring on both sides, we get

⇒  y² = x +5

⇒ x = y² -5

The range of the given function x = y² -5

the answer to the question is a

step-by-step explanation:

it has the same slope and the same y-intercept.

y + 11 = -7/9(x - 18)

y + 11 =-7/9x + 14

b

y = -7/9x + 3

y-intercept (0, 3)

i hope this is what you were looking for.

see attached graph