In the triangle ABC, 2BCA = 99 , AC = 23 in, and BA = 26 in. Determine the measure(s) of CBA to the nearest tenth.

  ∠CBA = 60.9°

Step-by-step explanation:

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  ∠CBA = 60.9°

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Since you have two sides and the angle opposite one of them you can find the angle opposite the other using the Law of Sines.

  (sin B)/b = (sin C)/c

  sin B = (b/c)sin C

  B = arcsin(b/c·sin(C)) = arcsin(23/26·sin(99°)) = arcsin(0.873824)

  B ≈ 60.8943° ≈ 60.9°

Angle CBA is about 60.9°.

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation: