The width of the rectangle is 2 more than the length. The area of the rectangle is 63 square inches. How long is the width?

9 inches

Step-by-step explanation:

Area of rectangle= length ×width

Let the length of the rectangle be x inches.

Width of rectangle= (x +2) inches

since the width is 2 more than the length.

63= x(x+2)

63= x(x) +2x

Bringing constant to one side,

x² +2x -63= 0

(x +9)(x-7) = 0 (factorise)

x+9= 0 or x-7= 0

x= -9 or x= 7

(reject)

width of rectangle

= 7+2

= 9 inches

*We reject x= -9 since the length of the rectangle cannot be a negative number.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

cant open file sorry!

step-by-step explanation: