Find the critical value of t for a sample size 27 and a 99% confidence level?

The critical values define the values to cut-off in a region where the test statistic does not belong

The critical value is

The given parameters are:

First, we calculate the significance level

Substitute 99% for CL

Express percentage as decimal

Next, calculate the degrees of freedom

Substitute 27 for n

At and , the critical value is -2.778715

So, we have:

Hence, the critical value is

Read more about critical values at:

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The critical value is T = 2.7787

Step-by-step explanation:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 27 - 1 = 26

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.7787

The critical value is T = 2.7787

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

c.)

step-by-step explanation: