A father is 4 times as old as his son. In 20 years the father will be twice as old as his son.. Find their present ages

x = the age of his son now, then the age of the father is 4x.

In 20 years,

son's age = x + 20

father's age = 4x + 20

solve the equation for x:

4x + 20 = 2(x + 20)

4x + 20 = 2x + 40

2x = 20

x = 10

So the age of his son now is 10, and the age of the the father now is 40.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?