Solve for n.
11(n β 1) + 35 = 3n
n = β6
n = β3
n = 3
n = 6...
Mathematics, 20.06.2020 03:57 ghetauto
Solve for n.
11(n β 1) + 35 = 3n
n = β6
n = β3
n = 3
n = 6
Answers: 1
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