Find the area of a triangle bounded by the y axis, the line f(x)=9−2/3x, and the line is perpendicular to f(x) that passes through the origin. Area=

Step-by-step explanation:

Equation of the line perpendicular to f(x) that passes through origin:

Intersection point:

,

Triangle formed with vertex A (0,9), O(0,0), and C (27/13, 51/26).

The height of the triangle is 27/13 with respect to the base OA

Now, the leftover is just applying the formula to find the area of the triangle.

I let you finish your own work. Good luck

i think it's b

step-by-step explanation:

because the graph is 2 above (0,0)

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12