WILL MARK BRAINLIEST!! Lorri took a 240 km trip to Waterloo. On her way there, her average speed was 120 km/h. She was stopped for speeding, so on her way home, her average speed was 80 km/h. What was her average speed, in km/h, for the entire round-trip?

Her average speed was 480 km/ 5h which is 96.

Step-by-step explanation: When she went there her speed 120 km/ h and if the distance was 240 km, then it took her 2 hours to get there. 240 divided by 120 is 2. When she returned her average speed was 80 km/h and since the distance was 240, 240 divided by 8 is 3 which means it took her 3 hours to get back home. She drove a total of 480 km , because the distance to the trip was 240 and the distance from the trip to the back was 240. 240 + 240 is 480. She drove a total of 480 km in 5 hours because it took her 2 hours to go there and 3 hours to come back . 480 km / 5h

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: