Expand and simlify: a)-2{3a-4{a-(2+a)]} b)5{3c-[d-2(c+d)]}

a) -2 [ 3a-4(a-2-a) ]

= -2[ 3a - 4×(-2) ]

= -2( 3a + 8 )

= -6a-16

b) 5 [ 3c- ( d-2c-2d ) ]

= 5 [ 3c - (-d -2c ) ]

= 5 ( 3c + d + 2c )

= 5 ( 5c + d )

= 25c + 5d

3.how is solving radical equations different than solving linear equations?

step-by-step explanation: