Suppose a (the word 'a' means starting amount is 1) radioactive substance decays at a rate of 5% per hour, what percent of the substance is left after 10 hours? (make sure you convert your answer from decimal to percent and round to the nearest whole percent)

The percentage of the substance is left after 10 hours is 60%.

Step-by-step explanation:

The expression representing the amount left after a certain period of decay is:

Here,

y = final amount

a = initial amount

r = decay rate

t = time taken

It is provided that:

a = 1

r = 5% / hour

t = 10 hours

Compute the percentage of the substance is left after 10 hours as follows:

The percentage is: 0.60 × 100 = 60%.

Thus, the percentage of the substance is left after 10 hours is 60%.

c. prove the lengths are the same.

step-by-step explanation:

you need to prove the segments are congruent. congruent segments have the same length. find the lengths of the segments using the distance formula, and compare them.

answer: c. prove the lengths are the same.

good luck!

cutie~