Select the correct answer from each drop-down menu. A quadrilateral has vertices A(11, -7), B(9, -4), C(11, -1), and D(13, -4). Quadrilateral ABCD is a . If the vertex C(11, -1) were shifted to the point C′(11, 1), quadrilateral ABC′D would be a .

Quadrilateral ABCD is a Quadrilateral with four equal sides so either a rhombus or square

But

Quadrilateral ABC'D is a quadrilateral with two adjacent sides equal so it's a kite shape

Step-by-step explanation:

(11, -7), B(9, -4), C(11, -1), and D(13, -4).

Let's take out the values of x and y coordinate with the way they are arranged

X = 11,9,11,13

Y = -7,-4,-1,-4

So we observe that distance of the coordinates on either x is 2 units and y is 3 units.

But when the the value was changed to

C′(11, 1), (11, -7), B(9, -4), C′(11, 1), and D(13, -4).

There was difference of 2 unit and 4 unit making the new shape a kite.

The diagram attached explain better

probably the last option

step-by-step explanation: