On a coordinate plane, a line goes through (negative 1, 1) and (0, negative 3). A point is at (negative 4, negative 3) and (0, negative 3). What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (−4, −3)? y + 3 = −4(x + 4) y + 3 = –One-fourth(x + 4) y + 3 = One-fourth(x + 4) y + 3 = 4(x + 4)

Step-by-step explanation:

Please mark me as brainlist

16

step-by-step explanation:

2 x 40 = 80

80/5

= 16

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1