PLZ HELP IM STUCK (c-d)/5 - 2 = 0
c-6d=0
Given the equations, what is the value of c/d?
PLZ HELP WILL MARK BRAINLIEST

On the first equation, which is (c-d)/5 - 2 = 0 Let's start by solving c.

First, you need to add 1/5d to both sides:

1/5 c + -1/5 d - 2 + 1/5 d = 0 + 1/5 d

1/5 c - 2 = 1/5 d

Next, add 2 to both sides:

1/5 c - 2 + 2 = 1/5 d + 2

1/5 c = 1/5 d + 2

Now, divide both sides by 1/5:

1/5 c/ 1/5 = 1/5 d + 2/ 1/5

c = d + 10

so, therefore, your answer is c = d + 10

Now we are going to do the 2nd equation, which is c-6d=0 Lets solve c.

The only thing you need to do is you need to add 6d to both sides:

c − 6d + 6d = 0 + 6d

c = 6d

So, therefore, your answer is c = 6d

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form