segment AB is dilated from the origin to create segment A prime B prime at A' (0, 8) and B' (8, 12). What scale factor was segment AB dilated by?

As you forgot to mention the diagram. I was able to find the diagram. Hence, I am attaching and solving the question based on that diagram, which anyways would clear your concept.

we conclude that the segment AB was dilated by scale factor 3.

Step-by-step explanation:

From the diagram, it is clear that the original points A and B are located

at (0, 2) and (2, 3) respectively.

i.e.

A(0, 2)

B(2, 3)

As the coordinates of the dilated segment A'B' are given as:

A'(0, 6)

B'(6, 9)

A scale factor is basically a number that multiplies an object or quantity.

For instance, the 'D' in  is the scale factor for x.

If the equation were y = 7x, then the factor would have been 5.

As the coordinates of the dilated segment A'(0, 6) and B'(6, 9) are 3 times the coordinates of the original segment A(0, 2) and B(2, 3).

i.e.

A(0, 2)  → (0×3, 2×3) = A'(0, 6)

B(2, 3) → (2×3, 3×3) = B'(6, 9)

Therefore, we conclude that the segment AB was dilated by scale factor 3.

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

a

step-by-step explanation: